Why you can't assume m(p) > 0 in your "proof" of m(p) > 0
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Posted by DickT on July 05, 2002 at 10:14:43:
In Reply to: Re: m1a) Why in the early steps of my proof I have to consider what happens if the mass of the photon = 0? posted by kx21 on July 04, 2002 at 22:25:34:
kx21, Because m(p) > 0 is what you are trying to prove. If you only consider the case m(p) > 0 from the start, then you aren't proving anything, you're just shuffling around different ways of assuming m(p) > 0. The cases you have to consider are all possible values of m(p); since I don't think you are considering negative masses, all cases means m(p) >= 0. The key value m(p) = 0 breaks your proof, because if m(p) = 0 then f(i) = 0 for all i and you can only conclude that Newtonian gravity does not act on photons. Regards, Dick
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