Re: Eureka X v3:- A Generalization- Newton's Gravitational forces ensured that the Mass of any given Particle is greater than Zero, with mathematical proof...

Posted by kx21 on July 03, 2002 at 14:01:42:

In Reply to: Quit spamming this site.. posted by James on July 03, 2002 at 11:33:49:

It would be good if all Forum users could target their comment on the specified point(s) of the given subject matter, for the sake & good of Forum, instead of politicized the 'matter'.

(A generalized version of Eureka X v2)

"A generalization worths a Thousand 'sincereless' comments..."

Eureka X v3:- Newton's Gravitational forces ensured that the Mass of any given Particle is greater than Zero

Proof:-

(1) Let the Total number of Massive physical Entities which have the 'appropriate' relationship(s) with the given Particle in the Cosmos is N. i.e. The mass of Entity i, m(i) > 0.

Newton's Graviational force:-

(2) f(i) = Gm(p)*m(i) / r(i)^2

Thus,

(3) Abs[f(i)] = G*Abs[m(p]*m(i) / (r(i)^2, i =1,2,...,N

Note:

(4) m(p): The Mass of the given Particle, in the physical world.
(4.1) m(i): The Mass of massive Physical Entity i in the Cosmos

(4.2) G: Gravitational Constant

(5) r(i): The distance between the given Particle & the Entity i.

(6) Meta Laws 3 of the Cosmos dynamics implies that r(i) > 0.

Thus,

(7) Abs[m(p)] = Sum of [ Abs[f(i)]* r(i)^ 2)/ m(i)]/ G * N.

(8) Assumed that the Movement of the Particle is affected by some of the Entities.

(9) For instance, Entity j. Then Abs[f(j)] > 0.

This (7) implies that

(10) the Sum of [ Abs[f(i)]* r(i)^ 2) / m(i)] / G*N is > 0.

And

(10.1) Abs[m(p)] > 0

Thus,

(11) m(p) > 0 as the mass of any physical entity can't be negative, by definition.

i.e. The mass of the given Particle is > 0.

This completes the proof.

Corollary of Eureka X v3:-

The Mass of all 'Massless' Particles (e.g. Neutrino, Photon) is > 0.

Any comments on points (1) to (11) are welcome.

Copyright 2002 All Rights Reserved kx21.com

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