Re: MPhysics 21: SR's E = SR's E= SQRT(p^2c^2+ m^2c^4) & p = ?

Posted by DickT on May 08, 2003 at 15:28:01:

In Reply to: MPhysics 21: SR's E = SR's E= SQRT(p^2c^2+ m^2c^4) & p = ? posted by kx21 on May 08, 2003 at 13:26:03:

Kx21,

p is the magnitude of the three dimensional momentum. There is a relativistic formula for that but I didn't use it I just eyballed about 1/3 the speed of light and used the formula mv as you said.

But notice I said "about 1/3 the speed of light". I wasn't claiming that formula mv was accurate, for it isn't, at high speeds. But there is some relativistic momentum equal to the one I chose and it is somewhere around 1/3 mc. The algebra I did is perfectly correct for the numbers I put in, and it's only the phrase "about 1/3 the speed of light" which is approximate.

Regards,
Dick

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Follow Ups: (Reload page to see most recent)

• MPhysics 21: Weapon of Mass Confusion (WMC) hidden in SR's E= SQRT(p^2c^2+ m^2c^4)... -- kx21 5/08/03 (0)
• Re: MPhysics 21: p = ?, 'p = 0' = ? & 'm = 0' = ? -- kx21 5/08/03 (0)
• MPhysics 21: SR's E = SR's E= SQRT(p^2c^2+ m^2c^4) & p = ? -- kx21 5/08/03 (0)

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